3.959 \(\int \frac{A+B x}{x^5 \sqrt{a+b x+c x^2}} \, dx\)

Optimal. Leaf size=231 \[ \frac{\left (8 a b B \left (5 b^2-12 a c\right )-A \left (48 a^2 c^2-120 a b^2 c+35 b^4\right )\right ) \tanh ^{-1}\left (\frac{2 a+b x}{2 \sqrt{a} \sqrt{a+b x+c x^2}}\right )}{128 a^{9/2}}+\frac{\sqrt{a+b x+c x^2} \left (128 a^2 B c-220 a A b c-120 a b^2 B+105 A b^3\right )}{192 a^4 x}-\frac{\sqrt{a+b x+c x^2} \left (-36 a A c-40 a b B+35 A b^2\right )}{96 a^3 x^2}+\frac{(7 A b-8 a B) \sqrt{a+b x+c x^2}}{24 a^2 x^3}-\frac{A \sqrt{a+b x+c x^2}}{4 a x^4} \]

[Out]

-(A*Sqrt[a + b*x + c*x^2])/(4*a*x^4) + ((7*A*b - 8*a*B)*Sqrt[a + b*x + c*x^2])/(24*a^2*x^3) - ((35*A*b^2 - 40*
a*b*B - 36*a*A*c)*Sqrt[a + b*x + c*x^2])/(96*a^3*x^2) + ((105*A*b^3 - 120*a*b^2*B - 220*a*A*b*c + 128*a^2*B*c)
*Sqrt[a + b*x + c*x^2])/(192*a^4*x) + ((8*a*b*B*(5*b^2 - 12*a*c) - A*(35*b^4 - 120*a*b^2*c + 48*a^2*c^2))*ArcT
anh[(2*a + b*x)/(2*Sqrt[a]*Sqrt[a + b*x + c*x^2])])/(128*a^(9/2))

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Rubi [A]  time = 0.276561, antiderivative size = 231, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 4, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.174, Rules used = {834, 806, 724, 206} \[ \frac{\left (8 a b B \left (5 b^2-12 a c\right )-A \left (48 a^2 c^2-120 a b^2 c+35 b^4\right )\right ) \tanh ^{-1}\left (\frac{2 a+b x}{2 \sqrt{a} \sqrt{a+b x+c x^2}}\right )}{128 a^{9/2}}+\frac{\sqrt{a+b x+c x^2} \left (128 a^2 B c-220 a A b c-120 a b^2 B+105 A b^3\right )}{192 a^4 x}-\frac{\sqrt{a+b x+c x^2} \left (-36 a A c-40 a b B+35 A b^2\right )}{96 a^3 x^2}+\frac{(7 A b-8 a B) \sqrt{a+b x+c x^2}}{24 a^2 x^3}-\frac{A \sqrt{a+b x+c x^2}}{4 a x^4} \]

Antiderivative was successfully verified.

[In]

Int[(A + B*x)/(x^5*Sqrt[a + b*x + c*x^2]),x]

[Out]

-(A*Sqrt[a + b*x + c*x^2])/(4*a*x^4) + ((7*A*b - 8*a*B)*Sqrt[a + b*x + c*x^2])/(24*a^2*x^3) - ((35*A*b^2 - 40*
a*b*B - 36*a*A*c)*Sqrt[a + b*x + c*x^2])/(96*a^3*x^2) + ((105*A*b^3 - 120*a*b^2*B - 220*a*A*b*c + 128*a^2*B*c)
*Sqrt[a + b*x + c*x^2])/(192*a^4*x) + ((8*a*b*B*(5*b^2 - 12*a*c) - A*(35*b^4 - 120*a*b^2*c + 48*a^2*c^2))*ArcT
anh[(2*a + b*x)/(2*Sqrt[a]*Sqrt[a + b*x + c*x^2])])/(128*a^(9/2))

Rule 834

Int[((d_.) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Sim
p[((e*f - d*g)*(d + e*x)^(m + 1)*(a + b*x + c*x^2)^(p + 1))/((m + 1)*(c*d^2 - b*d*e + a*e^2)), x] + Dist[1/((m
+ 1)*(c*d^2 - b*d*e + a*e^2)), Int[(d + e*x)^(m + 1)*(a + b*x + c*x^2)^p*Simp[(c*d*f - f*b*e + a*e*g)*(m + 1)
+ b*(d*g - e*f)*(p + 1) - c*(e*f - d*g)*(m + 2*p + 3)*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, g, p}, x] &&
NeQ[b^2 - 4*a*c, 0] && NeQ[c*d^2 - b*d*e + a*e^2, 0] && LtQ[m, -1] && (IntegerQ[m] || IntegerQ[p] || IntegersQ
[2*m, 2*p])

Rule 806

Int[((d_.) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> -Si
mp[((e*f - d*g)*(d + e*x)^(m + 1)*(a + b*x + c*x^2)^(p + 1))/(2*(p + 1)*(c*d^2 - b*d*e + a*e^2)), x] - Dist[(b
*(e*f + d*g) - 2*(c*d*f + a*e*g))/(2*(c*d^2 - b*d*e + a*e^2)), Int[(d + e*x)^(m + 1)*(a + b*x + c*x^2)^p, x],
x] /; FreeQ[{a, b, c, d, e, f, g, m, p}, x] && NeQ[b^2 - 4*a*c, 0] && NeQ[c*d^2 - b*d*e + a*e^2, 0] && EqQ[Sim
plify[m + 2*p + 3], 0]

Rule 724

Int[1/(((d_.) + (e_.)*(x_))*Sqrt[(a_.) + (b_.)*(x_) + (c_.)*(x_)^2]), x_Symbol] :> Dist[-2, Subst[Int[1/(4*c*d
^2 - 4*b*d*e + 4*a*e^2 - x^2), x], x, (2*a*e - b*d - (2*c*d - b*e)*x)/Sqrt[a + b*x + c*x^2]], x] /; FreeQ[{a,
b, c, d, e}, x] && NeQ[b^2 - 4*a*c, 0] && NeQ[2*c*d - b*e, 0]

Rule 206

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTanh[(Rt[-b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[-b, 2]), x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rubi steps

\begin{align*} \int \frac{A+B x}{x^5 \sqrt{a+b x+c x^2}} \, dx &=-\frac{A \sqrt{a+b x+c x^2}}{4 a x^4}-\frac{\int \frac{\frac{1}{2} (7 A b-8 a B)+3 A c x}{x^4 \sqrt{a+b x+c x^2}} \, dx}{4 a}\\ &=-\frac{A \sqrt{a+b x+c x^2}}{4 a x^4}+\frac{(7 A b-8 a B) \sqrt{a+b x+c x^2}}{24 a^2 x^3}+\frac{\int \frac{\frac{1}{4} \left (35 A b^2-40 a b B-36 a A c\right )+(7 A b-8 a B) c x}{x^3 \sqrt{a+b x+c x^2}} \, dx}{12 a^2}\\ &=-\frac{A \sqrt{a+b x+c x^2}}{4 a x^4}+\frac{(7 A b-8 a B) \sqrt{a+b x+c x^2}}{24 a^2 x^3}-\frac{\left (35 A b^2-40 a b B-36 a A c\right ) \sqrt{a+b x+c x^2}}{96 a^3 x^2}-\frac{\int \frac{\frac{1}{8} \left (-8 a B \left (15 b^2-16 a c\right )+5 A \left (21 b^3-44 a b c\right )\right )+\frac{1}{4} c \left (35 A b^2-40 a b B-36 a A c\right ) x}{x^2 \sqrt{a+b x+c x^2}} \, dx}{24 a^3}\\ &=-\frac{A \sqrt{a+b x+c x^2}}{4 a x^4}+\frac{(7 A b-8 a B) \sqrt{a+b x+c x^2}}{24 a^2 x^3}-\frac{\left (35 A b^2-40 a b B-36 a A c\right ) \sqrt{a+b x+c x^2}}{96 a^3 x^2}+\frac{\left (105 A b^3-120 a b^2 B-220 a A b c+128 a^2 B c\right ) \sqrt{a+b x+c x^2}}{192 a^4 x}-\frac{\left (8 a b B \left (5 b^2-12 a c\right )-A \left (35 b^4-120 a b^2 c+48 a^2 c^2\right )\right ) \int \frac{1}{x \sqrt{a+b x+c x^2}} \, dx}{128 a^4}\\ &=-\frac{A \sqrt{a+b x+c x^2}}{4 a x^4}+\frac{(7 A b-8 a B) \sqrt{a+b x+c x^2}}{24 a^2 x^3}-\frac{\left (35 A b^2-40 a b B-36 a A c\right ) \sqrt{a+b x+c x^2}}{96 a^3 x^2}+\frac{\left (105 A b^3-120 a b^2 B-220 a A b c+128 a^2 B c\right ) \sqrt{a+b x+c x^2}}{192 a^4 x}+\frac{\left (8 a b B \left (5 b^2-12 a c\right )-A \left (35 b^4-120 a b^2 c+48 a^2 c^2\right )\right ) \operatorname{Subst}\left (\int \frac{1}{4 a-x^2} \, dx,x,\frac{2 a+b x}{\sqrt{a+b x+c x^2}}\right )}{64 a^4}\\ &=-\frac{A \sqrt{a+b x+c x^2}}{4 a x^4}+\frac{(7 A b-8 a B) \sqrt{a+b x+c x^2}}{24 a^2 x^3}-\frac{\left (35 A b^2-40 a b B-36 a A c\right ) \sqrt{a+b x+c x^2}}{96 a^3 x^2}+\frac{\left (105 A b^3-120 a b^2 B-220 a A b c+128 a^2 B c\right ) \sqrt{a+b x+c x^2}}{192 a^4 x}+\frac{\left (8 a b B \left (5 b^2-12 a c\right )-A \left (35 b^4-120 a b^2 c+48 a^2 c^2\right )\right ) \tanh ^{-1}\left (\frac{2 a+b x}{2 \sqrt{a} \sqrt{a+b x+c x^2}}\right )}{128 a^{9/2}}\\ \end{align*}

Mathematica [A]  time = 0.235602, size = 176, normalized size = 0.76 \[ \frac{\sqrt{a+x (b+c x)} \left (8 a^2 x (A (7 b+9 c x)+2 B x (5 b+8 c x))-16 a^3 (3 A+4 B x)-10 a b x^2 (7 A b+22 A c x+12 b B x)+105 A b^3 x^3\right )}{192 a^4 x^4}-\frac{\left (A \left (48 a^2 c^2-120 a b^2 c+35 b^4\right )+8 a b B \left (12 a c-5 b^2\right )\right ) \tanh ^{-1}\left (\frac{2 a+b x}{2 \sqrt{a} \sqrt{a+x (b+c x)}}\right )}{128 a^{9/2}} \]

Antiderivative was successfully verified.

[In]

Integrate[(A + B*x)/(x^5*Sqrt[a + b*x + c*x^2]),x]

[Out]

(Sqrt[a + x*(b + c*x)]*(105*A*b^3*x^3 - 16*a^3*(3*A + 4*B*x) - 10*a*b*x^2*(7*A*b + 12*b*B*x + 22*A*c*x) + 8*a^
2*x*(2*B*x*(5*b + 8*c*x) + A*(7*b + 9*c*x))))/(192*a^4*x^4) - ((8*a*b*B*(-5*b^2 + 12*a*c) + A*(35*b^4 - 120*a*
b^2*c + 48*a^2*c^2))*ArcTanh[(2*a + b*x)/(2*Sqrt[a]*Sqrt[a + x*(b + c*x)])])/(128*a^(9/2))

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Maple [B]  time = 0.013, size = 417, normalized size = 1.8 \begin{align*} -{\frac{B}{3\,a{x}^{3}}\sqrt{c{x}^{2}+bx+a}}+{\frac{5\,bB}{12\,{a}^{2}{x}^{2}}\sqrt{c{x}^{2}+bx+a}}-{\frac{5\,{b}^{2}B}{8\,{a}^{3}x}\sqrt{c{x}^{2}+bx+a}}+{\frac{5\,{b}^{3}B}{16}\ln \left ({\frac{1}{x} \left ( 2\,a+bx+2\,\sqrt{a}\sqrt{c{x}^{2}+bx+a} \right ) } \right ){a}^{-{\frac{7}{2}}}}-{\frac{3\,Bcb}{4}\ln \left ({\frac{1}{x} \left ( 2\,a+bx+2\,\sqrt{a}\sqrt{c{x}^{2}+bx+a} \right ) } \right ){a}^{-{\frac{5}{2}}}}+{\frac{2\,Bc}{3\,{a}^{2}x}\sqrt{c{x}^{2}+bx+a}}-{\frac{A}{4\,a{x}^{4}}\sqrt{c{x}^{2}+bx+a}}+{\frac{7\,Ab}{24\,{a}^{2}{x}^{3}}\sqrt{c{x}^{2}+bx+a}}-{\frac{35\,A{b}^{2}}{96\,{a}^{3}{x}^{2}}\sqrt{c{x}^{2}+bx+a}}+{\frac{35\,A{b}^{3}}{64\,{a}^{4}x}\sqrt{c{x}^{2}+bx+a}}-{\frac{35\,A{b}^{4}}{128}\ln \left ({\frac{1}{x} \left ( 2\,a+bx+2\,\sqrt{a}\sqrt{c{x}^{2}+bx+a} \right ) } \right ){a}^{-{\frac{9}{2}}}}+{\frac{15\,A{b}^{2}c}{16}\ln \left ({\frac{1}{x} \left ( 2\,a+bx+2\,\sqrt{a}\sqrt{c{x}^{2}+bx+a} \right ) } \right ){a}^{-{\frac{7}{2}}}}-{\frac{55\,Abc}{48\,{a}^{3}x}\sqrt{c{x}^{2}+bx+a}}+{\frac{3\,Ac}{8\,{a}^{2}{x}^{2}}\sqrt{c{x}^{2}+bx+a}}-{\frac{3\,A{c}^{2}}{8}\ln \left ({\frac{1}{x} \left ( 2\,a+bx+2\,\sqrt{a}\sqrt{c{x}^{2}+bx+a} \right ) } \right ){a}^{-{\frac{5}{2}}}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((B*x+A)/x^5/(c*x^2+b*x+a)^(1/2),x)

[Out]

-1/3*B/a/x^3*(c*x^2+b*x+a)^(1/2)+5/12*B/a^2*b/x^2*(c*x^2+b*x+a)^(1/2)-5/8*B/a^3*b^2/x*(c*x^2+b*x+a)^(1/2)+5/16
*B/a^(7/2)*b^3*ln((2*a+b*x+2*a^(1/2)*(c*x^2+b*x+a)^(1/2))/x)-3/4*B/a^(5/2)*b*c*ln((2*a+b*x+2*a^(1/2)*(c*x^2+b*
x+a)^(1/2))/x)+2/3*B/a^2*c/x*(c*x^2+b*x+a)^(1/2)-1/4*A*(c*x^2+b*x+a)^(1/2)/a/x^4+7/24*A/a^2*b/x^3*(c*x^2+b*x+a
)^(1/2)-35/96*A/a^3*b^2/x^2*(c*x^2+b*x+a)^(1/2)+35/64*A/a^4*b^3/x*(c*x^2+b*x+a)^(1/2)-35/128*A/a^(9/2)*b^4*ln(
(2*a+b*x+2*a^(1/2)*(c*x^2+b*x+a)^(1/2))/x)+15/16*A/a^(7/2)*b^2*c*ln((2*a+b*x+2*a^(1/2)*(c*x^2+b*x+a)^(1/2))/x)
-55/48*A/a^3*b*c/x*(c*x^2+b*x+a)^(1/2)+3/8*A/a^2*c/x^2*(c*x^2+b*x+a)^(1/2)-3/8*A/a^(5/2)*c^2*ln((2*a+b*x+2*a^(
1/2)*(c*x^2+b*x+a)^(1/2))/x)

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Maxima [F(-2)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((B*x+A)/x^5/(c*x^2+b*x+a)^(1/2),x, algorithm="maxima")

[Out]

Exception raised: ValueError

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Fricas [A]  time = 6.06718, size = 1007, normalized size = 4.36 \begin{align*} \left [-\frac{3 \,{\left (40 \, B a b^{3} - 35 \, A b^{4} - 48 \, A a^{2} c^{2} - 24 \,{\left (4 \, B a^{2} b - 5 \, A a b^{2}\right )} c\right )} \sqrt{a} x^{4} \log \left (-\frac{8 \, a b x +{\left (b^{2} + 4 \, a c\right )} x^{2} - 4 \, \sqrt{c x^{2} + b x + a}{\left (b x + 2 \, a\right )} \sqrt{a} + 8 \, a^{2}}{x^{2}}\right ) + 4 \,{\left (48 \, A a^{4} +{\left (120 \, B a^{2} b^{2} - 105 \, A a b^{3} - 4 \,{\left (32 \, B a^{3} - 55 \, A a^{2} b\right )} c\right )} x^{3} - 2 \,{\left (40 \, B a^{3} b - 35 \, A a^{2} b^{2} + 36 \, A a^{3} c\right )} x^{2} + 8 \,{\left (8 \, B a^{4} - 7 \, A a^{3} b\right )} x\right )} \sqrt{c x^{2} + b x + a}}{768 \, a^{5} x^{4}}, -\frac{3 \,{\left (40 \, B a b^{3} - 35 \, A b^{4} - 48 \, A a^{2} c^{2} - 24 \,{\left (4 \, B a^{2} b - 5 \, A a b^{2}\right )} c\right )} \sqrt{-a} x^{4} \arctan \left (\frac{\sqrt{c x^{2} + b x + a}{\left (b x + 2 \, a\right )} \sqrt{-a}}{2 \,{\left (a c x^{2} + a b x + a^{2}\right )}}\right ) + 2 \,{\left (48 \, A a^{4} +{\left (120 \, B a^{2} b^{2} - 105 \, A a b^{3} - 4 \,{\left (32 \, B a^{3} - 55 \, A a^{2} b\right )} c\right )} x^{3} - 2 \,{\left (40 \, B a^{3} b - 35 \, A a^{2} b^{2} + 36 \, A a^{3} c\right )} x^{2} + 8 \,{\left (8 \, B a^{4} - 7 \, A a^{3} b\right )} x\right )} \sqrt{c x^{2} + b x + a}}{384 \, a^{5} x^{4}}\right ] \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((B*x+A)/x^5/(c*x^2+b*x+a)^(1/2),x, algorithm="fricas")

[Out]

[-1/768*(3*(40*B*a*b^3 - 35*A*b^4 - 48*A*a^2*c^2 - 24*(4*B*a^2*b - 5*A*a*b^2)*c)*sqrt(a)*x^4*log(-(8*a*b*x + (
b^2 + 4*a*c)*x^2 - 4*sqrt(c*x^2 + b*x + a)*(b*x + 2*a)*sqrt(a) + 8*a^2)/x^2) + 4*(48*A*a^4 + (120*B*a^2*b^2 -
105*A*a*b^3 - 4*(32*B*a^3 - 55*A*a^2*b)*c)*x^3 - 2*(40*B*a^3*b - 35*A*a^2*b^2 + 36*A*a^3*c)*x^2 + 8*(8*B*a^4 -
7*A*a^3*b)*x)*sqrt(c*x^2 + b*x + a))/(a^5*x^4), -1/384*(3*(40*B*a*b^3 - 35*A*b^4 - 48*A*a^2*c^2 - 24*(4*B*a^2
*b - 5*A*a*b^2)*c)*sqrt(-a)*x^4*arctan(1/2*sqrt(c*x^2 + b*x + a)*(b*x + 2*a)*sqrt(-a)/(a*c*x^2 + a*b*x + a^2))
+ 2*(48*A*a^4 + (120*B*a^2*b^2 - 105*A*a*b^3 - 4*(32*B*a^3 - 55*A*a^2*b)*c)*x^3 - 2*(40*B*a^3*b - 35*A*a^2*b^
2 + 36*A*a^3*c)*x^2 + 8*(8*B*a^4 - 7*A*a^3*b)*x)*sqrt(c*x^2 + b*x + a))/(a^5*x^4)]

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Sympy [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{A + B x}{x^{5} \sqrt{a + b x + c x^{2}}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((B*x+A)/x**5/(c*x**2+b*x+a)**(1/2),x)

[Out]

Integral((A + B*x)/(x**5*sqrt(a + b*x + c*x**2)), x)

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Giac [B]  time = 1.34663, size = 1193, normalized size = 5.16 \begin{align*} \text{result too large to display} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((B*x+A)/x^5/(c*x^2+b*x+a)^(1/2),x, algorithm="giac")

[Out]

-1/64*(40*B*a*b^3 - 35*A*b^4 - 96*B*a^2*b*c + 120*A*a*b^2*c - 48*A*a^2*c^2)*arctan(-(sqrt(c)*x - sqrt(c*x^2 +
b*x + a))/sqrt(-a))/(sqrt(-a)*a^4) + 1/192*(120*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))^7*B*a*b^3 - 105*(sqrt(c)*x
- sqrt(c*x^2 + b*x + a))^7*A*b^4 - 288*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))^7*B*a^2*b*c + 360*(sqrt(c)*x - sqr
t(c*x^2 + b*x + a))^7*A*a*b^2*c - 144*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))^7*A*a^2*c^2 - 440*(sqrt(c)*x - sqrt(
c*x^2 + b*x + a))^5*B*a^2*b^3 + 385*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))^5*A*a*b^4 + 1056*(sqrt(c)*x - sqrt(c*x
^2 + b*x + a))^5*B*a^3*b*c - 1320*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))^5*A*a^2*b^2*c + 528*(sqrt(c)*x - sqrt(c*
x^2 + b*x + a))^5*A*a^3*c^2 + 768*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))^4*B*a^4*c^(3/2) + 584*(sqrt(c)*x - sqrt(
c*x^2 + b*x + a))^3*B*a^3*b^3 - 511*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))^3*A*a^2*b^4 - 480*(sqrt(c)*x - sqrt(c*
x^2 + b*x + a))^3*B*a^4*b*c + 1752*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))^3*A*a^3*b^2*c + 528*(sqrt(c)*x - sqrt(c
*x^2 + b*x + a))^3*A*a^4*c^2 + 384*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))^2*B*a^4*b^2*sqrt(c) - 1024*(sqrt(c)*x -
sqrt(c*x^2 + b*x + a))^2*B*a^5*c^(3/2) + 2048*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))^2*A*a^4*b*c^(3/2) - 264*(sq
rt(c)*x - sqrt(c*x^2 + b*x + a))*B*a^4*b^3 + 279*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))*A*a^3*b^4 - 288*(sqrt(c)*
x - sqrt(c*x^2 + b*x + a))*B*a^5*b*c + 360*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))*A*a^4*b^2*c - 144*(sqrt(c)*x -
sqrt(c*x^2 + b*x + a))*A*a^5*c^2 - 384*B*a^5*b^2*sqrt(c) + 384*A*a^4*b^3*sqrt(c) + 256*B*a^6*c^(3/2) - 512*A*a
^5*b*c^(3/2))/(((sqrt(c)*x - sqrt(c*x^2 + b*x + a))^2 - a)^4*a^4)